MTH 101 (fall 2011) Assignment No. 1 Idea Solution

Solution

y=5x+9

From the given equation slop of line is 5

Since Slop of perpendicular line =m=-1/5

and y intercept is= 6

By slop intercept form

y=mx+b

y=-1/5x+6

another 1

Find equation of the line which is perpendicular to the line   

      y= 5x+9 and has y-intercept = 6.

I think correct ansewr is

y=5x+9 is darivative w.r.t x

dy/dx=5+0

m=5

then slope of normal is m= -1/5

for normal equation is (y-y1)m =(x-x1)

(y-6)-1/5=(x-0)

 -y1/5+6=x

-y+30=5x

y+5x-30=0

this is normal equation

for perpendicular is

y=mx+b

y=-1/5x+6