Answer of part A
Future Value = .PMT [((1 + I )n – 1) / i] Future Value = 5000[((1 + .0325)20- 1) / .0325] Future Value = 5000[((1.0325)20 – 1) / .0325] Future Value = 5000[(1.895837924 – 1) / .0325] Future Value = 5000[.895837924 / .0325] Future Value = 5000[27.56424382] Future Value = 137821.2191
Plan B However, under the second plan, he has to deposit Rs 10,000 every year with Interest rate of 7.5 percent compounded annually |
Answer of Part B Future Value = .PMT [((1 + I )n – 1) / i] Future Value = 10000[((1 + .075)- 1) / .075] Future Value = 10000[((1.075)10 – 1) / .075] Future Value = 10000[(2.061031562– 1) / .075] Future Value = 10000[1.061031562/ .075] Future Value = 10000[14.1470875] Future Value = 141470.875 |
c). You are required to analyze that which plan would be suitable for him while keeping in view his major concern: ‘The value of plan at the end of 10th year’. |
Answer of Part C 2nd plan is suitable for him while keeping in view his major concern |
d). What would be the change in your decision if the interest rate on second plan is also 6.5 percent? |
Answer of Part D “If interest rate of 2nd plan 6.5 percent then I will chose Plan A because using 6.5 percent |
interest rate the FV for Plan B will be 134944.22, which is lower than plan A”
|
No comments:
Post a Comment